# Phys-4420 thermodynamics & statistical mechanics spring 2006

 Дата канвертавання 21.04.2016 Памер 5.66 Kb.
 PHYS-4420 THERMODYNAMICS & STATISTICAL MECHANICS SPRING 2006 Class Activity - Class 3 January 24, 2006 Name________ANSWERS________________ __ When a system is taken from state i to state f along path iaf in the figure, Q = 50 cal and W = 20 cal. Along path ibf, Q = 36 cal. a) What is W along path ibf ? Along path iaf, U = Q – W = 50 cal – 20 cal = 30 cal Along path ibf, U is the same. Therefore, for path ibf W = Q – U = 36 cal – 30 cal W = 6 cal b) If W = – 13 cal for the curved return path fi, what is Q for this path? Along path fi, U = – 30 cal. Therefore, for path fi, Q = W + U = – 13 cal – 30 cal Q = – 43 cal c) Take Ui = 10 cal. What is Uf ? Uf = Ui + U = 10 cal + 30 cal Uf = 40 cal d) If Ub = 22 cal, what are the values of Q for path ib and bf ? Wibf = Wib + Wbf = 6 cal, but Wbf = 0, so Wib = 6 cal. For ib, Qib = Wib + Uib = 6 cal + 22 cal – 10 cal Qib = 18 cal For bf, Qbf = Wbf + Ubf = 0 + 40 cal – 22 cal Qbf = 18 cal

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